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solving some issues on fusion and debounce exercises
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@ -67,7 +67,7 @@ t(async ({ eq }) =>
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run(opDebounce(add, 200, { leading: true }), { delay: 70, count: 3 }),
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run(opDebounce(add, 100, { leading: true }), { delay: 140, count: 3 }),
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]),
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[1, 2]
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[1, 3]
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)
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)
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@ -65,22 +65,4 @@ t(({ eq }) =>
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)
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)
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t(({ eq }) =>
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// object mutability
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eq(
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fusion(Object.freeze({ a: { b: 1 } }), Object.freeze({ a: { b: 2 } })).a.b,
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3
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)
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)
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// other types
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t(({ eq }) => eq(fusion({ reg: /\w/ }, { reg: /\S/ }).reg, /\S/))
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t(({ eq }) => {
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const set = new Set([1, 2, 3])
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return eq(fusion({ a: 1, set: new Set([4, 5, 6]) }, { a: 1, set }), {
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a: 2,
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set,
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})
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})
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Object.freeze(tests)
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@ -4,36 +4,37 @@
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The objective of this exercise is to merge objects into a new object depending on the values type
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With this create a function called `fusion` that:
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With this, create a function called `fusion` that:
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- If the type is an array you must concat it
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- If the type is an array you must concatenate it
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```js
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fusion([1, 2], [3, 4]) // -> [1,2,3,4]
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fusion({ arr: [1, "2"] }, { arr: [2] }); // -> { arr: [ 1, '2', 2 ] }
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fusion({ arr: [], arr1: [5] },{ arr: [10, 3], arr1: [15, 3], arr2: ["7", "1"] }); // ->{ arr: [ 10, 3 ], arr1: [ 5, 15, 3 ], arr2: [ '7', '1' ] }
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```
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- If it is a string you must concatenate with a space
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- If it is a string you must concatenate it with a space
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```js
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fusion('Salem', 'alem') // -> 'Salem alem'
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fusion({ str: "salem" }, { str: "alem" }); // -> { str: 'salem alem' }
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fusion({ str: "salem" }, { str: "" }); // -> { str: 'salem ' }
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```
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- If it is numbers you must added them
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- If they are numbers, you must add them
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```js
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fusion(4, 11) // -> 15
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fusion({ a: 10, b: 8, c: 1 }, { a: 10, b: 2 }); // -> { a: 20, b: 10, c: 1 }
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```
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- If it is an object, you must join them recursively
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```js
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fusion({ a: 1, b: { c: "Salem" } }, { a: 10, x: [], b: { c: "alem" } }); // -> { a: 11, x: [], b: { c: 'Salem alem' } }
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fusion( { a: { b: [3, 2], c: { d: 8 } } },{ a: { b: [0, 3, 1], c: { d: 3 } } }); // -> { a: { b: [ 3, 2, 0, 3, 1 ], c: { d: 11 } } }
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```
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- In case of type mismatch you must replace it with the value of the second object
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```js
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fusion({ a: 'hello', b: [] }, { a: 4 })
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// -> { a: 4, b: [] }
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```
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- If it is an object you must fusion them recursively
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```js
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fusion({ a: 1, b: { c: 'Salem' } }, { a: 10, x: [], b: { c: 'alem' } })
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// -> { a: 11, x: [], b: { c: 'Salem alem' } }
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fusion({ a: "hello", b: [] }, { a: 4 }); // -> { a: 4, b: [] }
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```
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